Question:

ents <HW 16 - Chapter 5 - Sections 4-7 Problem 5.71 1 of 3 A Review The rod is supported by a ball-and-socket joint A and cables

ents
<HW 16 - Chapter 5 - Sections 4-7
Problem 5.71
1 of 3
A Review
The rod is supported by a ball-and-socket joint A and
cables BC and BD. Suppose that F = 800 N.
Hibbeler14.ch5.p71.jpg
Part C
Search
Determine the tension in the cable BD necessary for equilibrium of the rod.
Express your answer to three significant figures and include the appropriate units.
Z
2 m
C
D
?
HA
2 m
D
TBD =
Value
Units
3 m
Submit
Request Answer
B
E
3 m
3 m
F

ents <HW 16 - Chapter 5 - Sections 4-7 Problem 5.71 1 of 3 A Review The rod is supported by a ball-and-socket joint A and cables BC and BD. Suppose that F = 800 N. Hibbeler14.ch5.p71.jpg Part C Search Determine the tension in the cable BD necessary for equilibrium of the rod. Express your answer to three significant figures and include the appropriate units. Z 2 m C D ? HA 2 m D TBD = Value Units 3 m Submit Request Answer B E 3 m 3 m F

Answer

.
N
can
tension
in
tension
in BC
we
T
is
N
49 :7
So,
unit
veetor
along Bc is
coordinate of
point A = (0,0,0)
coordinate of point c= (0, -2,3)
B: (6,5,6)
Ds (0, 2, 3)
First, by symmetry,
that
CD:
Suppose
tension
Now,
F:-850
B : (0-6) 2 + (2-0)ġ + (3-0) f = -6ê - 2j + zic 100/- Vo+2+3- -
BC,
22 - 23+
So, Toc (@J. -12- Şjne
T=
+
Similar.
i larly
BD = -bê t
zŷ + 3
So
BD = - + { j + FAO
Sy TED
-ST +13+
SO
Net force
end B Fr TBC + Too
- 12T i +
+
7
+
+
+
+
at
FE
Now,
A
will be
z Ors.
So
since the rod is in equilibrico,
Net torque
about
(AE * E) + (AB x T)=0
(31)x(- 8so ) + ( 6 ) ( - 12T +
/ CTR) =०
2550 j
(259-30)
2550 - 347 -
2550 XZ.,
4 95 833 N
=o
36T
7
T-
36
So,
BC
= 495.833 N
PART
B
TBD
495.833 N
PA RTC
Now)
reaction
A
is
is
ES
Suppose
Ā = Axi + Ay ŷ + Az
Sina the
rod in equilibrium,
Fred to
Ē + Toc +
Teo)+ Ā
F + F + Ā -
(850 ) +(-121 i + $5 ) + Axê + my i + Az ens
= (A - 127) it Ay j + (Az
–850 + $) =
1323 -0 =
850 N
Ay = 0
part
Az -850 +
> Az = 850-
425 N
7
S9
Ax -
Ax= 1212
7
SO
20
- 850 -425 3

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. N can tension in tension in BC we T is N 49 :7 So, unit veetor along Bc is coordinate of point A = (0,0,0) coordinate of point c= (0, -2,3) B: (6,5,6) Ds (0, 2, 3) First, by symmetry, that CD: Suppose tension Now, F:-850 B : (0-6) 2 + (2-0)ġ + (3-0) f... Download the app for the rest