Question:

@ 61 Fri Nov 19 G 5 T ♡ + : b. What is the wavelength and frequency of the first four overtones for this guitar string? (Overton

@ 61
Fri Nov 19
G
5
T
♡
+ :
b. What is the wavelength and frequency of the first four overtones for this guitar string?
(Overtones: L=(n+1)*0.5 wavelength, where n is the numbered overtone)
1) 2 x 1200 = 400 H₂
3) v = 440 = 4x200=800H₂
2)* 34-A== 2*0,95 = 633m
4) y-540 - SX200 - 1000 Hz
y=30=3x200= 600 Hz
c. If the speed of sound in the air is given by:
293 x 337= 342. alm/s
1
Vw= 33),
273
273
Vw = (331 m/s)
T
273 K
and the temperature is 20 Celsius, how long after she plays the string will an audience member
18 meters away hear the fundamental frequency?
18
Vw
342.91
D.0823S
d. How long after she plays will the same audience member hear the first overtone?
e. If the guitarist walks towards the audience at 1.5 m/s while playing, what frequency will the
audience hear for the fundamental frequency?
navo
Vt vs
X 200 - 200.91 H2
f. What % difference is your answer to e from when the guitarist wasn't moving?
(209.91-200) X100 = 0.455 Am
200
g. For the same case as part e, what frequency will the audience hear for the first overtone?
2x 2009 H2
= W01.82 Hz
h. For the same case as part e, what fundamental frequency will the guitarist hear herself
playing?
i. If the guitarist walks across the stage from left to right at 1.5 m/s, neither getting closer or
further from a specific audience member, what frequency will that audience member hear from
the fundamental frequency? the fundamental frequency will remain
200 H2

@ 61 Fri Nov 19 G 5 T ♡ + : b. What is the wavelength and frequency of the first four overtones for this guitar string? (Overtones: L=(n+1)*0.5 wavelength, where n is the numbered overtone) 1) 2 x 1200 = 400 H₂ 3) v = 440 = 4x200=800H₂ 2)* 34-A== 2*0,95 = 633m 4) y-540 - SX200 - 1000 Hz y=30=3x200= 600 Hz c. If the speed of sound in the air is given by: 293 x 337= 342. alm/s 1 Vw= 33), 273 273 Vw = (331 m/s) T 273 K and the temperature is 20 Celsius, how long after she plays the string will an audience member 18 meters away hear the fundamental frequency? 18 Vw 342.91 D.0823S d. How long after she plays will the same audience member hear the first overtone? e. If the guitarist walks towards the audience at 1.5 m/s while playing, what frequency will the audience hear for the fundamental frequency? navo Vt vs X 200 - 200.91 H2 f. What % difference is your answer to e from when the guitarist wasn't moving? (209.91-200) X100 = 0.455 Am 200 g. For the same case as part e, what frequency will the audience hear for the first overtone? 2x 2009 H2 = W01.82 Hz h. For the same case as part e, what fundamental frequency will the guitarist hear herself playing? i. If the guitarist walks across the stage from left to right at 1.5 m/s, neither getting closer or further from a specific audience member, what frequency will that audience member hear from the fundamental frequency? the fundamental frequency will remain 200 H2

Answer

Given that
Foundamental frequency = 200 Hz
frequency of first overtone - 24200Hz
- 900 Hz
then,
then
T=
T = 100
.
-0.0025 sec
where I = Time period
Thus after 0.0025 sec audiend hear firest
overtone
a

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