Question:

2. a. A guitarist strums a guitar string that is 95 cm in length. If the fundamental frequency heard is 200 Hz, what is the spee

2. a. A guitarist strums a guitar string that is 95 cm in length. If the fundamental frequency
heard is 200 Hz, what is the speed of a wave through the guitar string? (Fundamental:
L=0.5 wavelength).
b. What is the wavelength and frequency of the first four overtones for this guitar string?
(Overtones: L=(n+1)*0.5 wavelength, where n is the numbered overtone)
c. If the speed of sound in the air is given by:
T
Vw = (331 m/s) V 273 K
and the temperature is 20 Celsius, how long after she plays the string will an audience member
18 meters away hear the fundamental frequency?
d. How long after she plays will the same audience member hear the first overtone?
e. If the guitarist walks towards the audience at 1.5 m/s while playing, what frequency will the
audience hear for the fundamental frequency?

2. a. A guitarist strums a guitar string that is 95 cm in length. If the fundamental frequency heard is 200 Hz, what is the speed of a wave through the guitar string? (Fundamental: L=0.5 wavelength). b. What is the wavelength and frequency of the first four overtones for this guitar string? (Overtones: L=(n+1)*0.5 wavelength, where n is the numbered overtone) c. If the speed of sound in the air is given by: T Vw = (331 m/s) V 273 K and the temperature is 20 Celsius, how long after she plays the string will an audience member 18 meters away hear the fundamental frequency? d. How long after she plays will the same audience member hear the first overtone? e. If the guitarist walks towards the audience at 1.5 m/s while playing, what frequency will the audience hear for the fundamental frequency?

Answer

we
know
The
formula of Doppler affect
na
n
vt vo
Vo - velocity of observer
& t vs
Jo.
sa velocity of source,
So
this
ş
case
or o
2 331 ms.
- 1.5 m/s.
n = 200 Hz.
si
apparent frequency
ne
E
331
331-1)
X 200
2009L.H2
Am.

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