F2
F
0.180 m
A square metal plate 0.18 m

Question

F2
F
0.180 m
A square metal plate 0.18 m
on each side is pivoted about
an axis through point 0 at its
center and perpendicular to
the plate. Calculate the net
torque about this axis due to
the three forces shown if the
magnitudes of the forces are
Fi = 18 N, F2 = 26 N, and F3
14 N. The plate and all forces
are in the plane of the page.
0.180 m
45°
F3

Kunduz · Accepted Answer

length of metal plate = 0.18 m.
fFz
A
Jfi
B
Also given
0.16
m
O
C
f = 26 N
D
45°
%
fi= IBN
F3 = 14 N.
f3
=
so we getta find Torque about axis o.
so perpendicular distance from pt. 0 = 0.18 = 0.0gm
2
From figure, distance Ao =
0.16 = 0.127m.
va
So
calculate torque about all the 3 forces
T = 0.127x188 sin 135
T = 1.62 Nm.
,
T = 0.1278 268 sin 135°
T =
T2
2.33
Nm,
%
3D
Tz
0.127 x 14 x sin go
T
1.78 Nm
Net Torque
I Net = 2.33 +1.781.62
= 2.49 Nm

F2 F 0.180 m A square metal plate 0.18 m on each side is pivoted about an axis through point 0 at its center and perpendicular t