Course Contents ... HW11 Calculate

Question

Course Contents> ... >> HW11 > Calculate the torque exerted by the friction on the wheel
Timer Notes Evaluate Feedback Print
(hrw8c11p82) A wheel of radius 0.290 m, which is moving initially at 41 m/s, rolls to a stop in 285 m. Calculate its linear acceleration(magnitude only)
Submit Answer Tries 0/10
Calculate its angular acceleration.(magnitude only)
Submit Answer Tries 0/10
The wheel's rotational inertia is 0.105 kg* m about its central axis. Calculate the torque exerted by the friction on the wheel, about the central axis.(N*m) (magnitude only)
Submit Answer Tries 0/10
Send

Kunduz · Accepted Answer

Given radicas of wheel (R) = 0.29 m
.
Initial speed (linear) (u) = 41 mis
Final
speed (w)
= omis
( as wheel stops)
Distance
travelled (s)
285 m
(a)
using
Newton's
3rd er of motion
- W2 + 2as
get.
v²u²
25
(4132
25
2x285
%3D
1
)
2.95 mis? (Approx.)
is 2.95 mis?,
Therefore magntiude of linear acceleration
(6.) If wheel only rolls without slipping
)
then-
angular acceleration (x) = Linear, acceleration (@
radius (R)
10. 2 radis 2 (Approx.)
radis?
2.95
0.29
0)
Now, torque
torque is given by -
IX
Moment of inertia in given (0.105 kg.m2)
.
T =
Here I =
T =
0.105 x 10.2
=
%3D
1.067 Nm
m] (Approx.)
.

Course Contents> ... >> HW11 > Calculate the torque exerted by the friction on the wheel Timer Notes Evaluate Feedback Print (hr