Anna holds a 11 D magnifier directly in front of her eye to get a close look at a 19-mm -diameter penny. Assume a typical 25 cm near point and a distance of 1.7 cm between the lens and the retina. Part A: What is the closest possible distance that she can hold the coin to have it appear in focus? Express your answer with the appropriate units. Answer: 6.7 cm Part B: At this distance, how large does the image of the coin appear on her retina? Express your answer with the appropriate units.
- So. so + । . formula used, So Si f (given) D = 11ml f = % f = 1/1ml = f = 100 cm =) ta If = 7.14 om (given) Sitx = 25 1 Si=25-X = Si = 25-1,7 Si= 23.3 cm image distance is on the left 'Thus it is conventionally negative Si = -23.3 con, . 4= ? ) JO t Si f - - = Si-f = ) So = f Si So f Si Si-f So (7014) ( 23.3) Con -23.3 - 7,14). 5.44 cm. A \ 9. S.