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Light with a wavelength of 654 nm fal

Question

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Light with a wavelength of 654 nm falls on double slits of width a, a distance d apart. The 8th order interference minimum is 11.8
cm from the central maximum on a screen 4.92 m away. The 2nd order diffraction minumum is at an angle of 1.78°
a) What is the distance d?
b) What is the width a?
A.
d = 5.26 x 10-5 m
B.
d = 2.32 x 10-4 m
d = 4.21 x 10-5 m
d = 2.18 x 104 m
THE. d = none of these answers
O'F. a = 5.26 x 10-5 m
G. a = 2.32 x 10-4 m
H. a = 4.21 x 10-5 m
1.
a = 2.18 x 10-4 m
J. a = none of these answers

Kunduz · Accepted Answer

Page Na
given by
Auss
= Condition of interference minimo is
You Had
Yn
=(n-1/₂ x D.
a
a = (n - %) 20
n 1/2
11.8 x 10-2
for n=8 & 2 = 18-1/2 x 654 x 10 9 xuga
x
Lieblint 12 = 2.04x10 mg
Nome of these
म
sino
= na
siulon
nd
१
- 2X 654x109
sin (1-789
-4.218105 m
9
= 4.21 x 105
108 m/ t. (Hoptions

-D Light with a wavelength of 654 nm falls on double slits of width a, a distance d apart. The 8th order interference minimum is