Question 9 B0/1 pt 53 99 0 Details A

Question

Question 9
<
>
B0/1 pt 53 99 0 Details
A disease spreads through a population. The number of
cases t days after the start of the epidemic is shown
below.
Days after start (t)
Number infected (N(t) thousand)
60
10
69
12
Assume the disease spreads at an exponential rate.
How many cases will there be on day 86?
thousand (Round your
answer to the nearest thousand)
On approximately what day will the number infected equal
sixty-nine thousand?
(Round your answer to the nearest whole number)
Question Help: Video Written Example
Add Work
Submit Question
Jump to Answer

Kunduz · Accepted Answer

Growth of infected is in exponential rate
xt
Nit) EN
initial Number infected
No
No
t time
x-rate of infection
Given N(t) = 10 thump to
Godays
N(4)
= 12 thans t=69 days.
(60)
10= No ę
0
-
e
12= Noe
À (69)
%
2)
69-60)
=
)
91
13
- e
qd = m(1.2)
ax=
x = ln (1-2)
-0.0203
१
17
If
t=86 days then
0.0203 (86)
N(+) = No e
0.0203 (60)
TO
No e
0.0203 ( 86-60]
N(4)
0.0203%26
0.527
- e
10
- e
N
....
-e
-
0.527
N(+) = 1oxe
= 16.94 thousan
= 11 thousand infected cases
If
%
69= No
-
N(+) = 69 thousand then
0.0203 (6)
0.0203(t-60) = m(6-9)
e
t-60 =
un (6.9)
-95.15
10 = No e
0.0203
t=60+95.15-155. 15 days
69 १ 0.0203(t-60)
+
cases will be 69 Thousand
155 days laporos)
0.0 6
0.0203 160)
a
lo
on

Question 9 < > B0/1 pt 53 99 0 Details A disease spreads through a population. The number of cases t days after the start of the