Question:

75 V 50 V 25 V OV cm 1 cm Part A Determine the magnitude and direction of the electric field at point 1 in the figure E1=(2500V/

75 V
50 V
25 V
OV
cm
1 cm
Part A
Determine the magnitude and direction of the electric field at point 1 in the figure
E1=(2500V/m,up)
E1+=(7500V/m,up)
E1-→=(3750V/m, down)
E1—-=(2500V/m, down)
Part B
Determine the magnitude and direction of the electric field at point 2 in the figure.
E2-=(2500V/m,up)
E2—-=(3750V/m, down)
E2--=(7500V/m.down)
E2-=(5000V/m,up)

75 V 50 V 25 V OV cm 1 cm Part A Determine the magnitude and direction of the electric field at point 1 in the figure E1=(2500V/m,up) E1+=(7500V/m,up) E1-→=(3750V/m, down) E1—-=(2500V/m, down) Part B Determine the magnitude and direction of the electric field at point 2 in the figure. E2-=(2500V/m,up) E2—-=(3750V/m, down) E2--=(7500V/m.down) E2-=(5000V/m,up)

Answer

croing for mulla
Part A
EV
€ =25
d
=25004
1x10-2
E = 25000/m (clown
Parto
E=25
No 2= 2500 / (esp)
IMEL

croing for mulla Part A EV € =25 d =25004 1x10-2 E = 25000/m (clown Parto E=25 No 2= 2500 / (esp) IMEL

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