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75 V 50 V 25 V OV cm 1 cm Part A Determine the magnitude and direction of the electric field at point 1 in the figure E1=(2500V/

75 V 50 V 25 V OV cm 1 cm Part A Determine the magnitude and direction of the electric field at point 1 in the figure E1=(2500V/m,up) E1+=(7500V/m,up) E1-→=(3750V/m, down) E1—-=(2500V/m, down) Part B Determine the magnitude and direction of the electric field at point 2 in the figure. E2-=(2500V/m,up) E2—-=(3750V/m, down) E2--=(7500V/m.down) E2-=(5000V/m,up)

75 V 50 V 25 V OV cm 1 cm Part A Determine the magnitude and direction of the electric field at point 1 in the figure E1=(2500V/m,up) E1+=(7500V/m,up) E1-→=(3750V/m, down) E1—-=(2500V/m, down) Part B Determine the magnitude and direction of the electric field at point 2 in the figure. E2-=(2500V/m,up) E2—-=(3750V/m, down) E2--=(7500V/m.down) E2-=(5000V/m,up)

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= 1 (Figure 1) shows cross sections of five closed surfaces S1, S2, and so on. Assume that qı = 5.0 C , q2 = 8.4 C.q3 = 1.3 C.qu = 8.4 C.q5 = -7.2 C, and 76 = -9.7 C. Part B 3 Figure < 1 of 1 Find the net electric flux passing through the surface S2. Expre

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= 1 (Figure 1) shows cross sections of five closed surfaces S1, S2, and so on. Assume that qı = 5.0 C , q2 = 8.4 C.q3 = 1.3 C.qu = 8.4 C.q5 = -7.2 C, and 76 = -9.7 C. Part B 3 Figure < 1 of 1 Find the net electric flux passing through the surface S2. Express your answer in newton meters squared per coulomb. -S2 to AEO 91 SA 95 Il lei E help N·mº/C 92 S5 S3 94 93 Submit Request Answer 96 Part C

A large, flat, horizontal sheet of charge has a charge per unit area of 30 PC/m2. The magnitude of the electric field just above the middle of the sheet equals: O a. 1.695 x 102 N/C O b. 1.695 N/C Oc 1.695 x 10-1 NIC O d. 1.695 x 103 N/C

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A large, flat, horizontal sheet of charge has a charge per unit area of 30 PC/m2. The magnitude of the electric field just above the middle of the sheet equals: O a. 1.695 x 102 N/C O b. 1.695 N/C Oc 1.695 x 10-1 NIC O d. 1.695 x 103 N/C

2. A metal ball with a mass of 6.0 x10-6 kg and a charge of +9.0 uC has a velocity of 8.2 x 103 m/s moving directly away from an infinite plane of charge with a charge distribution of +60.0 uC/m². If it is currently 10 m away from the plane of charge what

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2. A metal ball with a mass of 6.0 x10-6 kg and a charge of +9.0 uC has a velocity of 8.2 x 103 m/s moving directly away from an infinite plane of charge with a charge distribution of +60.0 uC/m². If it is currently 10 m away from the plane of charge what is its speed when it has traveled 5.0 m? {1.09 x 104 m/s