Question:

75 V 50 V 25 V OV cm 1 cm Part A Determine the magnitude and direction of the electric field at point 1 in the figure E1=(2500V/

75 V
50 V
25 V
OV
cm
1 cm
Part A
Determine the magnitude and direction of the electric field at point 1 in the figure
E1=(2500V/m,up)
E1+=(7500V/m,up)
E1-→=(3750V/m, down)
E1—-=(2500V/m, down)
Part B
Determine the magnitude and direction of the electric field at point 2 in the figure.
E2-=(2500V/m,up)
E2—-=(3750V/m, down)
E2--=(7500V/m.down)
E2-=(5000V/m,up)

75 V 50 V 25 V OV cm 1 cm Part A Determine the magnitude and direction of the electric field at point 1 in the figure E1=(2500V/m,up) E1+=(7500V/m,up) E1-→=(3750V/m, down) E1—-=(2500V/m, down) Part B Determine the magnitude and direction of the electric field at point 2 in the figure. E2-=(2500V/m,up) E2—-=(3750V/m, down) E2--=(7500V/m.down) E2-=(5000V/m,up)