Question:

You have an RC Circuit hooked up to a battery that you are testing for your company. This consists of a battery, resistor and ca

You have an RC Circuit hooked up to a battery that you are testing for your company. This consists of a battery, resistor and capacitor
all in series. You can assume the battery is ideal (no internal resistance).
You need to know how long it takes (time) in order for the capacitor to store 84.9 % of the maximum possible energy for this circuit.
The values for the battery, resistor and capacitor are below.
Battery = 4.85 V
=
Capacitor = 40.00 micro Farads (UF)
=
Resistor = 169.00 kilo Ohms (k S2)
Make sure to include units with your answer.
Hint: This is NOT the same question as asking how long it takes to have 84.9 % of the maximum voltage across the capacitor. Think
about how the capacitor energy and voltage relate to solve this.

You have an RC Circuit hooked up to a battery that you are testing for your company. This consists of a battery, resistor and capacitor all in series. You can assume the battery is ideal (no internal resistance). You need to know how long it takes (time) in order for the capacitor to store 84.9 % of the maximum possible energy for this circuit. The values for the battery, resistor and capacitor are below. Battery = 4.85 V = Capacitor = 40.00 micro Farads (UF) = Resistor = 169.00 kilo Ohms (k S2) Make sure to include units with your answer. Hint: This is NOT the same question as asking how long it takes to have 84.9 % of the maximum voltage across the capacitor. Think about how the capacitor energy and voltage relate to solve this.

Answer

: x
U = 84.9% * Umar
I CV? 0.849x Ź CVO
2
Vo
2
2
3
x
/
) V-
=> V= 0.921 Vo
Time constant ? = R(= 169x10 2 x 40x1067
6.765
Now , Us
Using V = Voll-ėt/7)
v
e
0.921= le
t- 17.16 s
Answer
-
Iné - t/6-76

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