Question:

6052 W 3012 w 9V 50 MF S What is the current at t=0 (right as S closes)? O 1.8 A 0.45A O 4.5A 18 A Question 2 1 pts What is the

6052
W
3012
w
9V
50 MF
S
What is the current at t=0 (right as S closes)?
O 1.8 A
0.45A
O 4.5A
18 A
Question 2
1 pts
What is the current after a very long (i.c. infinite) time?
O 18A
O 0.45 A
4.5A
OA
U
Question 3
1 pts
What is the time constant t?
O 0.1 ms
O 100ms
10 ms
1 ms
Question 4
1 pts
At what time does the capacitor reach half charge?
O 0.45 ms
O 0.69 ms
o
1.38 ms
1.12 ms

6052 W 3012 w 9V 50 MF S What is the current at t=0 (right as S closes)? O 1.8 A 0.45A O 4.5A 18 A Question 2 1 pts What is the current after a very long (i.c. infinite) time? O 18A O 0.45 A 4.5A OA U Question 3 1 pts What is the time constant t? O 0.1 ms O 100ms 10 ms 1 ms Question 4 1 pts At what time does the capacitor reach half charge? O 0.45 ms O 0.69 ms o 1.38 ms 1.12 ms

More Questions on Capacitors

View all
+ Charging and Discharging a Capacitor in an R-C Circuit
21 of 30
RA Review | Consta
W =
Submit
Learning Goal:
To understand the dynamics of a series R-C circuit.
Consider a series circuit containing a resistor of resistance R and a
capacitor of capacitanc

Physics

Capacitors Solutions

+ Charging and Discharging a Capacitor in an R-C Circuit 21 of 30 RA Review | Consta W = Submit Learning Goal: To understand the dynamics of a series R-C circuit. Consider a series circuit containing a resistor of resistance R and a capacitor of capacitance C connected to a source of EMF E with negligible internal resistance. The wires are also assumed to have zero resistance. Initially, the switch is open and the capacitor discharged. (Figure 1) Now that we have a feel for the state of the circuit in its steady state, let us obtain expressions for the charge of the capacitor and the current in the resistor as functions of ( and It) dg(t) Using these equations, we obtain da E 9 da(t) de dt dt R and then, RC 9(0)-CE RC time. We start with the loop rule: E – Vr - Vc = 0. Note that Vr(t) = f(t)r. Vo(t) = 940 Let us try to understand the processes that take place after the switch is closed. The charge of the capacitor, the current in the circuit, and, correspondingly, the voltages across the resistor and the capacitor, will be changing. Note that at any moment in time during the life of our circuit, Kirchhoffs loop rule holds and indeed, it is helpful: E - VR - Vc = 0, where VR is the voltage across the resistor, and Vc is the voltage across the capacitor. y Part 1 di Integrate both sides of the equation dg(0) 9C-CE Rc to obtain an expression for q (t) Express your answer in terms of any or all of E, R, t, and C. Enter exp(x) fore". ► View Available Hint(s) VAZO ? 9(t) = Figure 1 of 2 > Submit R Part 1 fo=0 Now differentiate (t) to obtain an expression for the current I (t). Express your answer in terms of any or all of E. R. t, and C. Enter exp(x) for e. C=9=0 EVO AL ? TO