4x2 + 36y2 + 40x + 72y - 8 = 0
Step 4 of

Question

4x2 + 36y2 + 40x + 72y - 8 = 0
Step 4 of 4: Find the coordinates of the two foci of this ellipse. Round your answer to two decimal places.
Answer
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Kunduz · Accepted Answer

Given: 4x² + 40 xt 3 6y²4724-820
To find: major axis endpoints
solution :
%
4x²+40% +36y?+724 +100 -100+36-36-820
7) 4x'+40x47100 + 36y?+72y+36 = 100 +3678
→ 45x+10x+25] +36Cyé+2y + 1] = 144
→ 4[x+5]? +36 7+0= 144
→ 4(x + 5)²
+36 (4+172 144
=> 22+5)?
2
144
2
144
THY
2
+ (y+UJ?
36
u
2
Comparing
with (x-4)² (YK) 2
+
1
a2
-
h = -5,ka - 1, a= 6, b=2
The first focus is (h-cok)
= (-452 - 5,-1)
= (-10.66,-1)
The second focus is (hte, k)
= (-5+462,-1)
= (0.66,-1)
Hence, coordinates are:
(1-10.64, ) and 10.66),
E1 (
-)

4x2 + 36y2 + 40x + 72y - 8 = 0 Step 4 of 4: Find the coordinates of the two foci of this ellipse. Round your answer to two decim