Question:

If a cup of coffee has temperature 92°C in a room where the ambient air temperature is 21°C, then, according to Newton's Law of Cooling, the temperature of the coffee after t minutes is T(t) = 21 + 71

If a cup of coffee has temperature 92°C in a room where the ambient air temperature is 21°C, then, according to Newton's Law of Cooling, the
temperature of the coffee after t minutes is T(t) = 21 + 71e^-t /45. What is the average temperature of the coffee during the first 32 minutes?

If a cup of coffee has temperature 92°C in a room where the ambient air temperature is 21°C, then, according to Newton's Law of Cooling, the temperature of the coffee after t minutes is T(t) = 21 + 71e^-t /45. What is the average temperature of the coffee during the first 32 minutes?

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