P Block - Group 17 Questions

Inorganic Chemistry

P Block - Group 17 Solutions

The illustration to the left represents a mixture of iodine (purple) and fluorine (green) molecules. If the molecules in the above illustration react to form IF3 according to the equation 12 + 3 F2-→ 2 IF3 , the limiting reagent is F the number of IF3 molecules formed is 2 and the number of I atoms/molecules in excess is 1

Inorganic Chemistry

P Block - Group 17 Solutions

3:X + Y: :Y: The Lewis representation above depicts a reaction between a halogen (blue) and a main-group element from group (red). In this representation, each Y atom needs atoms ofx. electron(s) to complete its octet, and gains these electrons by forming bond(s) with There are unshared electron pair(s) and bonding electron pair(s) in the product molecule. The bonds in the product are

Inorganic Chemistry

P Block - Group 17 Solutions

LENOI.) JUMUIDeodudacbormadadm/https://learn-us-east-1-prod-fleet02-xythos.content blackboardcdn.com/60952172d527a, Automatic Zoom 81.(77 in the 3rd edition) Hydrogen gas (a potential future fuel) can be formed by the reaction of methane with water according to the equation: CH_(g) + H2O(g) -> CO(g) + 3 H2(g) In a particular reaction, 25.5 L of methane gas (measured at a pressure of 732 torr and a temperature of 25 °C) mixes with 22.8 L of water vapor (measured at a pressure of 702 torr and a temperature of 125 °C). The reaction produces 26.2 L of hydrogen gas at STP. What is the percent yield of the reaction?

Inorganic Chemistry

P Block - Group 17 Solutions

Question 13 For each set of elements represented in this periodic table outline, identify the principal quantum number, n, and the azimuthal quantum number, l, for the highest energy electrons in Drag each label to the appropriate target. View Available Hint(s) Reset Help 11 = 0 -8 1= l= 1 71 = l= 2 3 4 11 = le 5 6 n = Submit Outer electron configurations The outer electron configuration of an element includes everything

Inorganic Chemistry

P Block - Group 17 Solutions

O ATOMS, IONS AND MOLECULES III Naming ionic compounds with common polyatomic ions Fill in the name and empirical formula of each ionic compound that could be formed from the ions in this table: Some ionic compounds cation anion empirical formula name of compound x 5 ? 2+ Pb NO, 3+ Fe 104 Na Bro

Inorganic Chemistry

P Block - Group 17 Solutions

Try again... O MEASUREMENT AND MATTER Addition and subtraction of measurements e Try Again Your answer is incorrect. • Row 1: Your answer is incorrect. Decide whether each proposed addition or subtraction of measurements is possible. If it is possible, write the result in the last column of the table. Be sure every answer you enter has the correct unit symbol. Is this possible? result proposed addition or subtraction x10 5 x ? 58.00 ml O) yes 27.00 mL + 31.00 ml = ? no 76.957 kg 77.000 kg - 43.000 g = ? O yes O no . yes 30.020 L 30.000 L + 20.000 mL = ? O no

Inorganic Chemistry

P Block - Group 17 Solutions

1A H He 3A 4A Li Be c N Ne Na Mg Si 3B 4B 5B 6B 7B Cl Ar -8B 1B 2B Ca Sc Ti Cr Mn Fe Co Ni Cu Zn Ga Ge Se Br Ko Give the spectroscopic notation (also called spdf notation) electron configuration of Br. Enter the subshells in the order in which they are filled. For example, for oxygen, the answer would be: 1522s22p4.

Inorganic Chemistry

P Block - Group 17 Solutions

ciel Cucos VISUALIZATION Drawing Lewis Structures | Clear F Available Electrons: 32 F C F F Create the Lewis structure of CF4. NOTE: do only the step asked for in each part and then click Check-don't work ahead to solve the final structure. Step 1. Count valence electrons in the molecule or ion. Do this by adding the periodic group numbers for each atom in the structure and adjusting for charge. Enter and Check Step 2. Connect each pair of bonded atoms with a single bond by dragging bonds onto the molecule. Each bond decreases the number of available electrons by 2. Check

Inorganic Chemistry

P Block - Group 17 Solutions

8A H He RA 3A 4A SA 6A 7A Li Be B C N o Ne Na Mg AI Si A P 3B 4B 5B 6B 7B8B- CH Ar IB 2B K Ca Sc TI Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr uration of F. Give the spectroscopic notation (also called spdf notation) electron co Enter the subshells in the order in which they are filled. For example, for oxygen, the answer would be: 1s22s22p4

Inorganic Chemistry

P Block - Group 17 Solutions

8A 1A 4p H He 2A 3A 4A SA 6A 3d 7A 4s Li Be B C N F o Ne 1 | 11 21 3p 3s Na Mg A1 Si P S CI Ar _ 3B 4B 5B 6B 7B 8B- 1B 2B K 2p Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br KI 2s Fill All Clear 1s Instructions: Add either a single electron or a pair of electrons to an orbital by clicking and dragging the arrow symbol onto the orbital box. To remove electrons from an orbital, click on the orbital box. Give the "box notation" (also called the "dash notation") electron configuration of Cl by filling electrons into the orbital spaces provided. Press Check when complete. Recheck Next (1 of 5) Show Approach 1st attempt Incorrect The diagram has the wrong number of electrons. This element has 17 electrons.

Inorganic Chemistry

P Block - Group 17 Solutions

Hybridisation is intermixing of atomic orbitals of central atom in a molecule. Number of hybrid orbitals so formed is equal to number of atomic orbitals mixed together. On the basis of hybridisation of central atom the shape of a molecule can be predicted. Read Less Consider the ions formed when I2C16 acts as ionizing solvent. Identify the correct statement(s). Cationic part is linear Anionic part involves d-orbitals in hybridisation Cationic part is bent shape having hybridisation sp Anionic part contains bond angles of 90°

Inorganic Chemistry

P Block - Group 17 Solutions

ia Com | My Home OWLv2 | Onlir X + c east.cengagenow.com/ilrn/takeAssignment/takeCovalentActi... * M Gmail YouTube Maps BE RE Chapter 8: EOC [References] uestion 18 1 pt _uestion 19 1 pt a. Predict the molecular structure and bond angles for PCL3 . Approximate bond angles are sufficient question 20 1 pt Molecular Structure Question 21 1 pt Bond Angles = Question 22 1 pr Question 23 1 pt 6. Predict the molecular structure and bond angles for IC15. Approximate bond angles are sufficient Question 24 1 pt Molecular Structure = Question 25 1 pt Bond Angles Question 26 1 pt Question 27 1 pr Submit Answer Try Another Version Question ze. 1 p Visited hpts remaining Question 29 1 pr Question 30 Question 31 1 pr Question 32 1 pr Question 33 1 pr Progress 20133 items Due Jun 27 at Previous Next 66°F 10:39 AM 6/24/2021