Question:

1.49 moles of hydrogen gas are reacted with excess carbon monoxide according to the reaction below. If 15.5 grams of methanol (CH₂OH) are produced, what was the percent yield? 2 H₂(g) + CO(g) → CH₃OH(

1.49 moles of hydrogen gas are reacted with excess carbon monoxide according to the reaction below. If 15.5 grams of methanol (CH₂OH) are produced, what was the percent yield?
2 H₂(g) + CO(g) → CH₃OH(l)
(A) 59.1 %
(B) 64.9 %
(C) 68.5 %
(D) 72.3 %
(E) 79.19%
(F) 45.9 %

1.49 moles of hydrogen gas are reacted with excess carbon monoxide according to the reaction below. If 15.5 grams of methanol (CH₂OH) are produced, what was the percent yield? 2 H₂(g) + CO(g) → CH₃OH(l) (A) 59.1 % (B) 64.9 % (C) 68.5 % (D) 72.3 % (E) 79.19% (F) 45.9 %